2x(x-3)=10x^2-13x

Solution for 2x(x-3)=10x^2-13x equation:

2x(x-3)=10x^2-13x

We move all terms to the left:

2x(x-3)-(10x^2-13x)=0

We multiply parentheses

2x^2-6x-(10x^2-13x)=0

We get rid of parentheses

2x^2-10x^2-6x+13x=0

We add all the numbers together, and all the variables

-8x^2+7x=0

a = -8; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-8)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-8}=\frac{-14}{-16}
=7/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-8}=\frac{0}{-16}
=0
$